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In your session, the NLS.

In your session, the NLS._DAE_FORMAT is DD- MM- YYYY.There are 86400 seconds in a day.Examine

this result:

DATE

02-JAN-2020

Which statement returns this?

A.

SELECT TO_ CHAR(TO_ DATE(‘29-10-2019’) +INTERVAL ‘2’; MONTH + INTERVAL ‘5’; DAY -

INTERVAL ‘86410’ SECOND, ‘ DD-MON-YYYY’) AS "date"

FROM DUAL;

B.

SELECT TO_ CHAR(TO_ DATE(‘29-10-2019’) + INTERVAL ‘3’ MONTH + INTERVAL ‘7’ DAY -

INTERVAL ‘360’ SECOND, ‘ DD-MON-YYYY’) AS "date"

FROM DUAL;

C.

SELECT To CHAR(TO _DATE(‘29-10-2019’) + INTERVAL ‘2’ NONTH + INTERVAL ‘5’ DAY

INEERVAL ‘120’ SECOND, ‘ DD-MON-YYY) AS "date"

FROM DUAL;

D.

SELECT-TO_CHAR(TO _DATE(‘29-10-2019’+ INTERVAL ‘2’ MONTH+INTERVAL ‘6’ DAYINTERVAL

‘120’ SECOND, ‘DD-MON-YY’) AS "daTe"

FROM DUAL;

E.

SELECT-TO_CHAR(TO _DATE(‘29-10-2019’+ INTERVAL ‘2’ MONTH+INTERVAL ‘4’ DAYINTERVAL

‘120’ SECOND, ‘DD-MON-YY’) AS "daTe"

FROM DUAL;

Oracle 1z0-071 Summary

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  • Product: 1z0-071
  • Update on: Jul 25, 2025
  • Questions: 326
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