Given the bill of material (BOM) information below and independent requirements of 10 pieces (pcs)...

Given the bill of material (BOM) information, we can calculate the weekly gross requirement of component F by considering the independent requirements of Component A and B. For Component A, there is no direct requirement for Component F. For Component B, which has an independent requirement of 20 pcs per week, each requires 4 pcs of Component F according to its BOM. So, thetotal weekly gross requirement for Component F due to Component B is 204 = 80 pcs. Additionally, each piece of Component A requires 2 pieces of Component C according to its BOM and has an independent requirement of 10 pcs per week; hence requiring a total of 20 pieces of component C per week. Each piece of component C in turn requires 4 pieces of component F according to its BOM; hence requiring a total weekly gross requirement for component F due to component A is: 204 =80 pcs. Adding both gives us a total weekly gross requirement for component F as:80+80=160pcs. References:

•CPIM Part 1 Learning System, Module 4: Inventory Management, Section 4.2: Inventory Management Policies and Objectives

•CPIM Part 2 Learning System, Module 1: Supply Chain Strategy, Section 1.3: Capacity Management