The following components (1,2,3) each have reliabilities of 0.

Given that components 1, 2, and 3 each have reliabilities of 0.95, and assuming the system configuration as depicted in the image (series-parallel configuration):

Reliability of the parallel components (2 and 3): Rparallel=1−[(1−R2)×(1−R3)]R_{\text{parallel}} = 1 - [(1 - R_2) \times (1 - R_3)]Rparallel​=1−[(1−R2​)×(1−R3​)] Rparallel=1−[(1−0.95)×(1−0.95)]R_{\text{parallel}} = 1 - [(1 - 0.95) \times (1 - 0.95)]Rparallel​=1−[(1−0.95)×(1−0.95)] Rparallel=1−[0.05×0.05]R_{\text{parallel}} = 1 - [0.05 \times 0.05]Rparallel​=1−[0.05×0.05] Rparallel=1−0.0025R_{\text{parallel}} = 1 - 0.0025Rparallel​=1−0.0025 Rparallel=0.9975R_{\text{parallel}} = 0.9975Rparallel​=0.9975

Reliability of the entire system (series of component 1 and the parallel system): Rsystem=R1×RparallelR_{\text{system}} = R_1 \times R_{\text{parallel}}Rsystem​=R1​×Rparallel​ Rsystem=0.95×0.9975R_{\text{system}} = 0.95 \times 0.9975Rsystem​=0.95×0.9975 Rsystem=0.947625R_{\text{system}} = 0.947625Rsystem​=0.947625

Rounded to three decimal places, the system reliability is 0.948.