function myFunction() { a = a + b; var b = 1;}myFunction();console.

The correct answer is A , not D.

Inside myFunction(), the declaration:

var b = 1;

is hoisted to the top of the function scope, but only the declaration is hoisted, not the assignment. So internally, JavaScript treats the function approximately like this:

function myFunction() {

var b;

a = a + b;

b = 1;

}

Now examine this line:

a = a + b;

Before JavaScript can assign a value to a, it must first evaluate the right-hand side:

a + b

At this point:

b

exists locally because var b was hoisted, so its value is:

undefined

However:

a

has not been declared anywhere. Reading an undeclared variable causes a:

ReferenceError

So this line throws an error before assignment happens:

a = a + b;

Because the error occurs on that line, the next line inside the function is never executed:

var b = 1;

Also, because the error is not handled with try...catch, the program stops before reaching:

console.log(a);

console.log(b);

Therefore, the accurate statement is:

Line 02 throws a reference error, therefore line 03 is never executed.

So the verified answer is A .