Given the code below:01 function Person() {02 this.

Person.proto is being set, but JavaScript uses Person.prototype for the prototype chain, not Person.proto.

Therefore, job is not on Person.prototype, and instances of Person do not have job via prototype.

myFather is created with new Person(), so:

myFather.firstName is ' John ' .

myFather.job is undefined.

Attempting to call myFather.job() results in:

TypeError: myFather.job is not a function

So option A is correct.