A camera’s recording stream has a bitrate of 8 Mbit/s.

To calculate the storage used per hour by a camera’s recording stream with a bitrate of 8 Mbit/s, you can use the following formula:

Storage (GB/hour)=bitrate (Mbit/s)×seconds per hour8×1024\text{Storage (GB/hour)} = \frac{\text{bitrate (Mbit/s)} \times \text{seconds per hour}}{8 \times 1024}Storage (GB/hour)=8×1024bitrate (Mbit/s)×seconds per hour​

Since there are 3600 seconds in an hour:

Storage (GB/hour)=8×36008×1024=288008192=3.6 GB\text{Storage (GB/hour)} = \frac{8 \times 3600}{8 \times 1024} = \frac{28800}{8192} = 3.6 \text{ GB}Storage (GB/hour)=8×10248×3600​=819228800​=3.6 GB

Thus, the camera uses 3.6 GB of storage per hour. Axis documentation on storage requirements for video streams provides similar calculations to estimate storage needs based on bitrate.